- #1
thinktank75
- 19
- 0
How do you calculate the absolute error of an experiment (in moles of acides) when you are given:
18.59 +/-0.02mL of a 12.85 +/ 0.03M NaOh solution that is going to be neutralized with an unknown acid?
I'm not sure how to plug it into the equation, or I may be using the wrong equation.
Thanks
18.59 +/-0.02mL of a 12.85 +/ 0.03M NaOh solution that is going to be neutralized with an unknown acid?
I'm not sure how to plug it into the equation, or I may be using the wrong equation.
Thanks