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How to calculate any 8 digits, to two 4 digit combinations?

  1. Aug 16, 2011 #1
    Could Someone tell me how to calculate any 8 digits, to two 4 digit combinations, with non of them repeating/conflicting except for the two 5's, such as

    4589, 8945? the 8 digits i'm specifically interested in is 23455689?

    please don't give just a formula, unless you can explain how to input on a standard calculator. thanks in advance...
     
    Last edited: Aug 16, 2011
  2. jcsd
  3. Aug 16, 2011 #2

    Mark44

    Staff: Mentor

    You're going to have to be clearer. I have no idea whatsoever what you're trying to say here. None of this makes any sense to me.
     
  4. Aug 16, 2011 #3

    gb7nash

    User Avatar
    Homework Helper

    Maybe someone else can figure this out, but I can't tell what you're asking. Are you given two 4 digit numbers? Do you want to do something with these two 4-digit numbers and come up with some 8-digit number? What are you trying to do?

    At least I'm not the only one.
     
  5. Aug 16, 2011 #4
    it's just a theory i have for nyc's win4. i noticed that alot of the time these numbers

    2,3,4,5,5,6,8,9 came up out of the various combos, in fact it came up the 2 most recent times.

    http://nylottery.org/wps/portal/!ut...ttery/winning+numbers/win4pastwinning+numbers

    08/16/2011 Midday 5-6-3-9
    08/15/2011 Evening 8-2-9-6

    http://www.endmemo.com/math/randomorder.php

    this site helped, but i'm just too lazy to try all combos until it repeats. just tell me if it's 42(guess) times or what... and how to do the formula on a standard

    calculator? Remember they must not repeat/conflict except for the two 5's... hope this makes sense now! Possible additions: 7-1-0

    edit: 08/16/2011 Evening 5-4-9-6

    See!
    Am I Right or Am I Right? Just didn't play that combo today! Darn "2"... scan0012.jpg
    in case your wondering what "box" means, it's just that any order comprised of the winners wins...
     
    Last edited: Aug 16, 2011
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