How to calculate any 8 digits, to two 4 digit combinations?

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Discussion Overview

The discussion revolves around calculating combinations of 8 digits into two 4-digit combinations, specifically focusing on the digits 23455689, with the condition that no digits repeat except for the two occurrences of the digit 5. Participants seek clarification on the method and how to perform calculations using a standard calculator.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant requests a method to calculate two 4-digit combinations from the digits 23455689, emphasizing the need for clarity and calculator instructions.
  • Another participant expresses confusion over the initial request, questioning the intent and clarity of the problem presented.
  • A third participant reiterates the lack of understanding, asking for clarification on whether two 4-digit numbers are given or if the goal is to derive something from them.
  • A later post introduces a theory related to a lottery game, suggesting that certain combinations of digits frequently appear, and requests assistance in determining the number of combinations without repetition, while also seeking guidance on using a calculator for this purpose.
  • The same participant shares past winning numbers and expresses frustration over missing a potential winning combination, indicating a personal investment in the topic.

Areas of Agreement / Disagreement

Participants generally do not agree on the clarity of the original question, with multiple views on what is being asked and how to approach the problem. The discussion remains unresolved regarding the specific method to calculate the combinations.

Contextual Notes

There are limitations in the clarity of the initial request, and participants express uncertainty about the intended calculations and the conditions for the combinations.

itoikenza
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Could Someone tell me how to calculate any 8 digits, to two 4 digit combinations, with non of them repeating/conflicting except for the two 5's, such as

4589, 8945? the 8 digits I'm specifically interested in is 23455689?

please don't give just a formula, unless you can explain how to input on a standard calculator. thanks in advance...
 
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itoikenza said:
Could Someone tell me how to calculate any 8 digits, to two 4 digit combinations, with non of them repeating/conflicting except for the two 5's, such as

4589, 8945? the 8 digits I'm specifically interested in is 23455689?
You're going to have to be clearer. I have no idea whatsoever what you're trying to say here. None of this makes any sense to me.
itoikenza said:
please don't give just a formula, unless you can explain how to input on a standard calculator. thanks in advance...
 
Maybe someone else can figure this out, but I can't tell what you're asking. Are you given two 4 digit numbers? Do you want to do something with these two 4-digit numbers and come up with some 8-digit number? What are you trying to do?

Mark44 said:
You're going to have to be clearer. I have no idea whatsoever what you're trying to say here. None of this makes any sense to me.

At least I'm not the only one.
 
it's just a theory i have for nyc's win4. i noticed that a lot of the time these numbers

2,3,4,5,5,6,8,9 came up out of the various combos, in fact it came up the 2 most recent times.

http://nylottery.org/wps/portal/!ut...ttery/winning+numbers/win4pastwinning+numbers

08/16/2011 Midday 5-6-3-9
08/15/2011 Evening 8-2-9-6

http://www.endmemo.com/math/randomorder.php

this site helped, but I'm just too lazy to try all combos until it repeats. just tell me if it's 42(guess) times or what... and how to do the formula on a standard

calculator? Remember they must not repeat/conflict except for the two 5's... hope this makes sense now! Possible additions: 7-1-0

edit: 08/16/2011 Evening 5-4-9-6

See! Am I Right or Am I Right? Just didn't play that combo today! Darn "2"...
scan0012.jpg

in case your wondering what "box" means, it's just that any order comprised of the winners wins...
 
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