How to calculate any 8 digits, to two 4 digit combinations?

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The discussion revolves around calculating two 4-digit combinations from a specific set of 8 digits (23455689) without repeating any digits, except for the two 5's. Participants express confusion over the original request, seeking clarification on the intended calculation process. The user mentions a theory related to NYC's Win4 lottery, noting that certain combinations frequently appear. They also reference external resources for generating combinations but express frustration over the manual effort required. The conversation highlights the need for a clear explanation of the calculation method on a standard calculator.
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Could Someone tell me how to calculate any 8 digits, to two 4 digit combinations, with non of them repeating/conflicting except for the two 5's, such as

4589, 8945? the 8 digits I'm specifically interested in is 23455689?

please don't give just a formula, unless you can explain how to input on a standard calculator. thanks in advance...
 
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itoikenza said:
Could Someone tell me how to calculate any 8 digits, to two 4 digit combinations, with non of them repeating/conflicting except for the two 5's, such as

4589, 8945? the 8 digits I'm specifically interested in is 23455689?
You're going to have to be clearer. I have no idea whatsoever what you're trying to say here. None of this makes any sense to me.
itoikenza said:
please don't give just a formula, unless you can explain how to input on a standard calculator. thanks in advance...
 
Maybe someone else can figure this out, but I can't tell what you're asking. Are you given two 4 digit numbers? Do you want to do something with these two 4-digit numbers and come up with some 8-digit number? What are you trying to do?

Mark44 said:
You're going to have to be clearer. I have no idea whatsoever what you're trying to say here. None of this makes any sense to me.

At least I'm not the only one.
 
it's just a theory i have for nyc's win4. i noticed that a lot of the time these numbers

2,3,4,5,5,6,8,9 came up out of the various combos, in fact it came up the 2 most recent times.

http://nylottery.org/wps/portal/!ut...ttery/winning+numbers/win4pastwinning+numbers

08/16/2011 Midday 5-6-3-9
08/15/2011 Evening 8-2-9-6

http://www.endmemo.com/math/randomorder.php

this site helped, but I'm just too lazy to try all combos until it repeats. just tell me if it's 42(guess) times or what... and how to do the formula on a standard

calculator? Remember they must not repeat/conflict except for the two 5's... hope this makes sense now! Possible additions: 7-1-0

edit: 08/16/2011 Evening 5-4-9-6

See! Am I Right or Am I Right? Just didn't play that combo today! Darn "2"...
scan0012.jpg

in case your wondering what "box" means, it's just that any order comprised of the winners wins...
 
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Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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