How to Calculate Concentration in a First Order Reaction?

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SUMMARY

The discussion focuses on calculating the concentration of a first-order reaction involving the decomposition of compound AB, with a rate constant (k) of 2.3 x 10-7 s-1 at 45°C. The initial concentration is given as 0.25 M, and the concentration after 2.3 minutes is derived using the equation ln[A]t = -kt + ln[A]0. The correct application of logarithmic principles leads to the final concentration of AB being 0.25 M after the specified time.

PREREQUISITES
  • Understanding of first-order reaction kinetics
  • Familiarity with natural logarithms and their properties
  • Knowledge of the equation ln[A]t = -kt + ln[A]0
  • Basic algebra skills for solving logarithmic equations
NEXT STEPS
  • Study the derivation and applications of the first-order reaction rate equation
  • Learn how to solve logarithmic equations effectively
  • Explore the concept of half-life in first-order reactions
  • Investigate the impact of temperature on reaction rates using the Arrhenius equation
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Chemistry students, educators, and anyone interested in mastering reaction kinetics and logarithmic calculations in chemical reactions.

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Homework Statement



The decomposition of AB is first order with a k = 2.3 x 10-7 s-1 at 45oC. If the initial concentration is 0.25 M, the concentration after 2.3 min is:

Homework Equations



ln[A]t = -kt x ln[A]0

The Attempt at a Solution



I have subbed in the values I have but I am not getting the right answer. I am unable to solve the logarithmic equation and need help there but also need to know if my method is correct.

I have subbed in:

ln[A]t = -2.3 x 10-7 x 138 (seconds) x ln.25

I am getting :

ln[A]t = 4.4 x 10-5

My problem is that I cannot remember how to solve that equation for [A]t. It's been a while since i looked at logarithmic equations. I have done google searches for the past hour and tried a few things but can't solve it. I'm not sure if my method is even correct in the first place.

Please help.
 
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YES! I have figured it out. Sometimes I wonder if I have the aptitue to learn this chemistry stuff, but I am doing well so far and I am teaching myself so it's obviously not going to be easy all the way. Anyway.. this was where I left off last time.


ln[AB]t = -2.3 x 10-7 x 138 (seconds) + ln.25
= -1.386

ln[AB]138 = -1.386
[AB] = e-1.386 **This is the step that was killing me, simple logarithmic algebra)**

[AB] = .25M


Now, let's see how I get on with the rest of the problems!
 

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