How to Calculate Contact Force Between Boxes in Physics?

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SUMMARY

The discussion focuses on calculating the contact forces between three boxes under a net force of 7.50 N. The masses of the boxes are m1 = 1.30 kg, m2 = 3.10 kg, and m3 = 5.80 kg. The correct approach to find the contact force between boxes 1 and 2 involves recognizing that both m2 and m3 are being pushed by the force acting on m1, while the contact force between boxes 2 and 3 is derived from the acceleration affecting only m3. The acceleration is calculated as 0.735 m/s², which is used to determine the contact forces accurately.

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  • Understanding Newton's Second Law of Motion
  • Basic knowledge of force and mass relationships
  • Ability to calculate acceleration from net force and total mass
  • Familiarity with contact forces in a system of connected objects
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Homework Statement



As shown in Figure 5-19, a force of magnitude 7.50 N pushes three boxes with masses m1 = 1.30 kg, m2 = 3.10 kg, and m3 = 5.80 kg.

Figure 5-19
the figure depicts 3 boxes, in order m1, m2, m3 with a force pushing directly on m1 to the right on a flat level surface.

(a) Find the contact force between boxes 1 and 2.
N
(b) Find the contact force between between boxes 2 and 3.
N

Homework Equations



I know you solve for acceleration by taking the fnet of 7.5 N and dividing it by the total mass to get .735 N.

i then was able to get part b by multiplying a, or .735, by the m3, or 5.8 which was the correct answer. however, when i did the same thing for part one, by multiplying a by m2 to get the contact foirce, i was incorrect. please help and explain
 
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papi said:

Homework Statement



As shown in Figure 5-19, a force of magnitude 7.50 N pushes three boxes with masses m1 = 1.30 kg, m2 = 3.10 kg, and m3 = 5.80 kg.

Figure 5-19
the figure depicts 3 boxes, in order m1, m2, m3 with a force pushing directly on m1 to the right on a flat level surface.

(a) Find the contact force between boxes 1 and 2.
N
(b) Find the contact force between between boxes 2 and 3.
N

Homework Equations



I know you solve for acceleration by taking the fnet of 7.5 N and dividing it by the total mass to get .735 N.

i then was able to get part b by multiplying a, or .735, by the m3, or 5.8 which was the correct answer. however, when i did the same thing for part one, by multiplying a by m2 to get the contact foirce, i was incorrect. please help and explain

The contact force between the blocks will come from the blocks that the force is not yet acting through, that is the blocks that are being pushed.

That means your acceleration applied to the masses it is still pushing ahead of the contact point is the source of your contact force.

In part b) the only mass it is pushing is m3. But in part a) you are pushing both m2 and m3.
 

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