1. The problem statement, all variables and given/known data Three boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0 kg, 3.0 kg, and 2.0 kg, with the 3.0-kg mass in the center. A force of 50 N pushes on the 5.0-kg mass, which pushes against the other two masses. What is the contact force between the 3.0-kg mass and the 2.0 kg mass? a) 25 N b) 10 N c) 40 N d) 0 N 2. Relevant equations Maybe F = m a? 3. The attempt at a solution [ 5 kg ] [ 3 kg ] [ 2 kg ] I would think that gravity would diminish the applied force of 50 N. Fg = m g Fg = 5 kg * 10 m / s^2 Fg = 50 N So the 50 N force would be subtracted from the applied force of 50 N, leaving 0 N, right? I'm confused. Can someone help me? Thank you!