How to Calculate pH of a 0.15 M Solution of Potassium Hydroxide Using Kw Value

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SUMMARY

The calculation of pH for a 0.15 M solution of potassium hydroxide (KOH) involves using the ionization of strong bases and the ion product of water (Kw). The hydroxide ion concentration is determined as [OH-] = 0.15 M, leading to a pOH of 0.824. The pH is then calculated using the relationship pH + pOH = 14, resulting in a final pH of 13.18. This method confirms the strong base's complete ionization in dilute solutions.

PREREQUISITES
  • Understanding of strong base ionization
  • Knowledge of pH and pOH calculations
  • Familiarity with the ion product of water (Kw)
  • Basic logarithmic functions
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  • Learn about the ion product of water (Kw) and its significance in acid-base chemistry
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Homework Statement


A strong base cane be assumed to be fully ionised in dilute solution. Use the Kw value to calculate the hydrogen ion concentration and hence the pH of a 0.15 M solution of potassium hydroxide, KOH.

Homework Equations


The Attempt at a Solution



Problem is, I don't know where to begin, so any advice on how to proceed or pointers would be appreciated.
 
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Yeah, I think I managed to do it meself. Forgot it was a strong base.

pOH=-log10[OH-]
pOH=-log10[0.15M]
pOH=0.824

pH+pOH=14 ∴ pH=14-0.824=13.176
 
Too many digits - 13.18 would be more to my liking. Other than that you did OK.
 

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