How to Calculate Power and Energy Usage in Electrical Devices

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The discussion focuses on calculating the power and energy usage of a blow-dryer and a vacuum cleaner, both operating at 120 V. The blow-dryer consumes approximately 1.6 kW, while the vacuum cleaner's power consumption is significantly lower. The ratio of energy used by the blow-dryer over 21 minutes to that used by the vacuum cleaner in 30 minutes is determined to be 3. Participants clarify the use of the equations for power and energy, emphasizing the importance of correct unit conversion and understanding the variables involved. Overall, the thread highlights common misunderstandings in applying electrical formulas.
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A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 13 A, and that of the vacuum cleaner is 3.0 A.
(a) Determine the power consumed by the blow-dryer.
1 W

(b) Determine the power consumed by the vacuum cleaner.
2 W

(c) Determine the ratio of the energy used by the blow-dryer in 21 minutes to the energy used by the vacuum cleaner in one-half hour.
Ebd / Evc = 3



Relevant Equations R=E^2/P
I=E/R

I mostly get confusedon what E is and what R is in the problem
 
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Hello johnson!

I'm afraid I just don't see how you get yours answers for Part a) and b). Here, we could use the equation P = IV, so for eg part a), I get approximately 1.6 kW, not 1 W. I think there may be a misunderstanding here.

For part c), Power is the rate of Energy per time, ie P = E/t. Rearrang the equation for E (Energy). We can work out how much energy each item takes by then replacing P with the value we got earlier, and t with the time we are told (remember to convert to SI units). Then we can divide appropriately to get the ratio.

We don't need R anywhere.
 
thanks soo much...i just figured out that I messed up the equations like crazy...i have the right answers now.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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