How to Calculate Second Order Correlation from Master Equation?

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The discussion centers on calculating second-order correlation from the master equation for bosonic operators, specifically concerning the factorization of terms like <aa^{+}a^{+}a>. The participants clarify that normal-ordering is essential to account for measurement effects on the light field, and that the term <a^{+}a^{+}aa> does not simply factorize to <n><n(t)>. They emphasize the complexity of finding solutions, which varies based on the type of light field, with references provided for further reading on lasers and quantum fields. The final insight suggests using the Heisenberg equation for calculations, particularly when determining cross-correlations between generated quantum fields. Understanding the time dependence of correlation functions is crucial for accurate calculations.
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Hi,
I have a problem in calculating the second order correlation (coherence) from the master equation for the operators \sigma and a a[+][/SUP] , because I don't know if
<aa^{+}a^{+}a> can be factorized to<a><n><a>.
I want to do this calculation directly from the density matrix solution.
thanks
 
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This problem is not immediately clear to me. Do you want to calculate the second-order coherence for some light field?

If that is the case, I assume the operators are bosonic, but what exactly does \sigma denote?
And how exactly do you get the \langle \hat{a} \hat{a}^\dagger \hat{a}^\dagger \hat{a} \rangle term? Usually you consider normal-ordering of the operators to account for the effect of the measurement on the light field and get terms like \langle \hat{a}^\dagger \hat{a}^\dagger \hat{a} \hat{a} \rangle.
 
yes you right about the normal ordering, the sigma are the atomic transition operators.
the problem is that when I calculate the mean values of these operators in time, how can I know the second order coherence. can I factorize the expression <A+A+AA> (the plus is dagger) to(<n><n(t)>)? if you know on some reference I will really appreciate it too.
 
Unfortunately, the \langle \hat{a}^\dagger \hat{a}^\dagger \hat{a} \hat{a} \rangle- term does not factorize to \langle \hat{n} \hat{n} \rangle.
Starting with the equal time correlation, you have \hat{a}^\dagger \hat{a} =\hat{a}\hat{a}^\dagger -1, so that the above term factorizes to \langle \hat{n} (\hat{n}-1) \rangle.

This makes sense as the detection of a photon changes the light field by destroying that photon. However, if you are interested in the time dependence of the correlation function, the term \hat{a}^\dagger (t+\tau) \hat{a}(t) can be anything from \hat{a} (t) \hat{a}^\dagger(t+\tau) -1 to \hat{a} (t) \hat{a}^\dagger(t+\tau) depending on the magnitude of \tau compared to the coherence time of the light.

Finding a solution for this problem is rather demanding and depends on the kind of light field you are interested in. I suppose you are interested in lasers. "Classical" atom lasers are for example discussed within a birth-death model in "Photon statistics of a cavity-QED laser: A comment on the laser–phase-transition analogy" by P.R. Rice and H.J. Carmichael, Phys. Rev. A 50, 4318–4329 (1994). Semiconductor lasers are treated using the cluster expansion method in "Semiconductor model for quantum-dot-based microcavity lasers" by C. Gies et al., Phys. Rev. A 75, 013803 (2007).

If you could tell me what kind of system or light field you have in mind, I might be able to come up with more suitable references for your case.
 
Hi
thanks for the help, actually I read the papers as you suggested and I track for more and I find the thing that I want. apparently, in order to calculate the the \left\langle[/a^{+}/a^{+}aa]\right\rangle we have to use the Heisenberg equation for it which depend on the other operators, where in some place I can use factorization in order to get a solution. let&#039;s say I have to generated quantum fields a_{1},a_{2} so in order to find their cross correlation I have to calculate the \left\langle a^{+}_{1}(t)a^{+}_{2}(t+\tau)a_{2}(t+tau)a_{1}(t)\right\rangle in this case what is the difference between t and t+\tau. and maybe because of that we can factorize earlier in the derivations.<br /> thanks for your help
 
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