How to Calculate the Distance of a Free Falling Object Without Air Resistance?

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To calculate the distance a free-falling object falls without air resistance, the relevant equations of motion must be applied. In this case, the flowerpot takes 0.420 seconds to fall past a 1.90-meter-high window. The discussion emphasizes the importance of identifying known variables and relevant equations, such as those for uniformly accelerated motion. Participants are encouraged to share their thoughts and attempts at solving the problem rather than seeking direct answers. Engaging with the problem using a structured approach will lead to a better understanding of the concepts involved.
kero
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Can somebody please show me how to solve this problem?

A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes the pot 0.420 s to pass this window, which is 1.90 m high. How far is the top of the window below the windowsill from which the flowerpot fell?
Thank you
 
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kero said:
Can somebody please show me how to solve this problem?

A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes the pot 0.420 s to pass this window, which is 1.90 m high. How far is the top of the window below the windowsill from which the flowerpot fell?
Thank you
Welcome to Physics Forums.

We will help you with your homework, but we won't do it for you. What are the relevant equations? What have you tried already? What are your thoughts on the problem? We have a homework template for a reason, please use it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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