How to Calculate the Distance of a Free Falling Object Without Air Resistance?

[kero]

Can somebody please show me how to solve this problem?

A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes the pot 0.420 s to pass this window, which is 1.90 m high. How far is the top of the window below the windowsill from which the flowerpot fell?
Thank you

 

[Hootenanny]

Can somebody please show me how to solve this problem?

A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes the pot 0.420 s to pass this window, which is 1.90 m high. How far is the top of the window below the windowsill from which the flowerpot fell?
Thank you

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[tomcue]

for your question. To solve this problem, we can use the equation d = 1/2 * g * t^2, where d is the distance, g is the acceleration due to gravity (9.8 m/s^2), and t is the time. In this case, we know the time (0.420 s) and the distance (1.90 m), so we can rearrange the equation to solve for the initial height (h) of the flowerpot before it fell. This gives us h = d / (1/2 * g * t^2) = 1.90 m / (1/2 * 9.8 m/s^2 * (0.420 s)^2) = 1.90 m / 0.08772 m = 21.68 m. Therefore, the top of the window below the windowsill is 21.68 meters from the windowsill. I hope this helps!