- #1

Manassa Mauler

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I would love someone to verify the answer for equation 8 in this paper (bottom of page 263) http://onlinelibrary.wiley.com/doi/10.1046/j.1365-2028.2002.00368.x/epdf

For the sake of clarity here is the equation is LaTeX which you can render at the following link

\frac{QC + Q\lambda \sigma - T(_{Ema + \frac{_{Emc}}{2}}))}{2k + \frac{2Qd}{V}}

https://www.codecogs.com/latex/eqneditor.php

The inputs are:

Q = 5.2 * 10^6 Joules

C =1.5 kg

lambda = 0.055 kg per hour

sigma = 12 hours

T = 48 hours

Ema = 42 Watts

Emc =24 Watts

k=2 Joules per meter

V =45 km per hour

The answer should be 205 km

Thanks!

For the sake of clarity here is the equation is LaTeX which you can render at the following link

\frac{QC + Q\lambda \sigma - T(_{Ema + \frac{_{Emc}}{2}}))}{2k + \frac{2Qd}{V}}

https://www.codecogs.com/latex/eqneditor.php

The inputs are:

Q = 5.2 * 10^6 Joules

C =1.5 kg

lambda = 0.055 kg per hour

sigma = 12 hours

T = 48 hours

Ema = 42 Watts

Emc =24 Watts

k=2 Joules per meter

V =45 km per hour

The answer should be 205 km

Thanks!

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