- #1
Manassa Mauler
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I would love someone to verify the answer for equation 8 in this paper (bottom of page 263) http://onlinelibrary.wiley.com/doi/10.1046/j.1365-2028.2002.00368.x/epdf
For the sake of clarity here is the equation is LaTeX which you can render at the following link
\frac{QC + Q\lambda \sigma - T(_{Ema + \frac{_{Emc}}{2}}))}{2k + \frac{2Qd}{V}}
https://www.codecogs.com/latex/eqneditor.php
The inputs are:
Q = 5.2 * 10^6 Joules
C =1.5 kg
lambda = 0.055 kg per hour
sigma = 12 hours
T = 48 hours
Ema = 42 Watts
Emc =24 Watts
k=2 Joules per meter
V =45 km per hour
The answer should be 205 km
Thanks!
For the sake of clarity here is the equation is LaTeX which you can render at the following link
\frac{QC + Q\lambda \sigma - T(_{Ema + \frac{_{Emc}}{2}}))}{2k + \frac{2Qd}{V}}
https://www.codecogs.com/latex/eqneditor.php
The inputs are:
Q = 5.2 * 10^6 Joules
C =1.5 kg
lambda = 0.055 kg per hour
sigma = 12 hours
T = 48 hours
Ema = 42 Watts
Emc =24 Watts
k=2 Joules per meter
V =45 km per hour
The answer should be 205 km
Thanks!
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