How to calculate the mass within the Hubble Sphere?

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Discussion Overview

The discussion focuses on calculating the mass within the Hubble Sphere and its time dependence, specifically within the context of the ΛCDM model.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant suggests calculating the mass by determining the average density and multiplying it by the volume, referencing Jorrie's calculator for assistance.
  • Another participant states that the density of the universe is close to the critical density, proposing the formula ##\rho=\frac {3H^2}{8\pi G}## for density and the Hubble radius as ##c/H##, leading to a derived mass of the Hubble volume as ##\frac{ c^3 H}{2G}##.
  • A later reply reiterates the mass calculation, emphasizing that the mass of the Hubble volume decreases in proportion to the Hubble parameter.
  • Another participant confirms the mass formula and notes that it grows in proportion to how the Hubble parameter decreases.

Areas of Agreement / Disagreement

Participants present similar calculations regarding the mass of the Hubble volume, but there are nuances in how they interpret the relationship between mass and the Hubble parameter, indicating some level of disagreement or uncertainty.

Contextual Notes

The discussion includes assumptions about the critical density and the dependence on the Hubble parameter, which may not be fully resolved.

timmdeeg
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How to calculate the mass within the Hubble Sphere and its time dependence, assuming the L-CDM model?
 
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Calculate the average density, multiply by the volume. I think most of that can be got out of Jorrie's calcuator.
 
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The density of the universe is very close to the critical density, that is, we can consider it to be ##\rho=\frac {3H^2}{8\pi G}##. On the other hand, the Hubble radius is ##c/H## so the Hubble volume is ##\frac{4\pi c^3}{3H^3}##. The mass of the Hubble volume is density times volume ##\frac {3H^2}{8\pi G}\frac{4\pi c^3}{3H^3}=\frac{ c^3 H}{2G}##. From the above it follows that the mass of the Hubble volume decreases in proportion to the Hubble parameter.

Edit:
The mass of the Hubble volume is density times volume ##\frac {3H^2}{8\pi G}\frac{4\pi c^3}{3H^3}=\frac{ c^3 }{2HG}##.
From the above it follows that the mass of the Hubble volume grows in proportion to how the Hubble parameter decreases
 
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Jaime Rudas said:
The mass of the Hubble volume is density times volume ##\frac {3H^2}{8\pi G}\frac{4\pi c^3}{3H^3}=\frac{ c^3 }{2HG}##.
From the above it follows that the mass of the Hubble volume grows in proportion to how the Hubble parameter decreases
Thanks for clarifying.
 

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