How to calculate the mass within the Hubble Sphere?

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SUMMARY

The calculation of mass within the Hubble Sphere is based on the L-CDM model, where the average density is derived from the critical density formula, ##\rho=\frac {3H^2}{8\pi G}##. The Hubble radius is defined as ##c/H##, leading to the Hubble volume calculation of ##\frac{4\pi c^3}{3H^3}##. Consequently, the mass of the Hubble volume is expressed as ##\frac{ c^3 }{2HG}##, indicating that this mass decreases in proportion to the Hubble parameter's decrease over time.

PREREQUISITES
  • Understanding of the L-CDM cosmological model
  • Familiarity with the critical density formula in cosmology
  • Knowledge of Hubble's law and the Hubble parameter
  • Basic principles of volume calculation in three-dimensional space
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  • Explore the relationship between the Hubble parameter and cosmic expansion
  • Investigate the role of dark energy in the context of the Hubble Sphere
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Astronomers, cosmologists, and physics students interested in the dynamics of the universe and the implications of the Hubble Sphere on cosmic mass calculations.

timmdeeg
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How to calculate the mass within the Hubble Sphere and its time dependence, assuming the L-CDM model?
 
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Calculate the average density, multiply by the volume. I think most of that can be got out of Jorrie's calcuator.
 
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The density of the universe is very close to the critical density, that is, we can consider it to be ##\rho=\frac {3H^2}{8\pi G}##. On the other hand, the Hubble radius is ##c/H## so the Hubble volume is ##\frac{4\pi c^3}{3H^3}##. The mass of the Hubble volume is density times volume ##\frac {3H^2}{8\pi G}\frac{4\pi c^3}{3H^3}=\frac{ c^3 H}{2G}##. From the above it follows that the mass of the Hubble volume decreases in proportion to the Hubble parameter.

Edit:
The mass of the Hubble volume is density times volume ##\frac {3H^2}{8\pi G}\frac{4\pi c^3}{3H^3}=\frac{ c^3 }{2HG}##.
From the above it follows that the mass of the Hubble volume grows in proportion to how the Hubble parameter decreases
 
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Jaime Rudas said:
The mass of the Hubble volume is density times volume ##\frac {3H^2}{8\pi G}\frac{4\pi c^3}{3H^3}=\frac{ c^3 }{2HG}##.
From the above it follows that the mass of the Hubble volume grows in proportion to how the Hubble parameter decreases
Thanks for clarifying.
 

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