How to Calculate the Probability of 13 Out of 408 Guessing a Birthday Correctly?

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Homework Help Overview

The discussion revolves around calculating the probability of 13 out of 408 people correctly guessing a birthday, framed within the context of probability theory and statistics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the binomial distribution as a method for calculating the probability, questioning the assumptions of independence and the accuracy of the model. There is also inquiry into the combinatorial function C(n, k) and its calculation.

Discussion Status

The discussion is active, with participants providing insights into the probability calculation and clarifying mathematical concepts. Some participants express uncertainty about statistical terminology and seek further explanation.

Contextual Notes

There is an acknowledgment of potential gaps in statistical knowledge among participants, as well as assumptions regarding the independence of guesses and the treatment of leap years.

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If 408 people try to guess someone's birthday, how do you calculate the chance of 13 of them being right? http://www.greasypalm.co.uk/gpforum/forum14/363.html
 
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Well, the chance of each individually being right is 1/365 (ignoring leap years and assuming people's guesses are independent of the person's actual birthday, which is probably not true), and if they are independent then it follows the binomial distribution, so the answer is
C(408, 13) * (1/365)^13 * (364/365)^395. Unless you're interested in the probability of at least 13 being right.
 
Last edited:
Sorry, statistics represents a bit of a gap in my education. What is this C function, and how do I calculate it/look it up?

Let's go with exactly 13 of them being right.
 
C(n, k) = \frac{n!}{(k!)(n-k)!}
 
Last edited:
Thanks. 1 in 5,370,675,393 I make it.
 

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