Calculating Weight Ratio of PEO and LiClO4 in PEO-LiClO4-Al2O3 PE Samples

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SUMMARY

The discussion centers on calculating the weight ratio of Polyethylene Oxide (PEO) and Lithium Perchlorate (LiClO4) in PEO-LiClO4-Al2O3 polymer electrolyte samples. When the oxygen to lithium ion ratio (n) is set to 10, the calculation reveals that the weight ratio of PEO to LiClO4 is approximately 4:1. This is derived from the PEO formula C2n H4n+2 On+1, where n=9 results in a total weight of 414.49432 grams for PEO and a molar mass of LiClO4 at 106.39 g/mol.

PREREQUISITES
  • Understanding of polymer chemistry, specifically PEO and its chemical structure.
  • Knowledge of molar mass calculations and weight ratios.
  • Familiarity with the properties and applications of Lithium Perchlorate (LiClO4).
  • Experience with basic laboratory techniques, including ultrasonication and solution preparation.
NEXT STEPS
  • Research the properties of PEO and its applications in polymer electrolytes.
  • Learn about the synthesis and characterization of PEO-LiClO4 composites.
  • Explore the role of Al2O3 in enhancing the performance of polymer electrolytes.
  • Investigate the impact of varying the n ratio on the electrochemical properties of PEO-LiClO4 systems.
USEFUL FOR

Chemists, materials scientists, and engineers involved in the development of polymer electrolytes for batteries and energy storage systems will benefit from this discussion.

SPEOTW
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TL;DR
Weight ratio calculation of a compound
So i found this on a journal, and im wondering what is n and how can i calculate the weight percentage ratio between the PEO and LiClO4. Here is the instruction.

To prepare PEO-LiClO4-Al2O3 PE samples, predetermined amounts of LiClO4 (such that oxygen to lithium ion ratio is n:1) and Al2O3 (as a percentage of the total weight of the (PEO)nLiClO4 PEs) were dissolved and ultrasonicated in anhydrous acetonitrile.

Can someone help me if n = 10 what is the weight ratio between PEO and LiClO4.
 
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Not clear to me if they mean molar or mass ratio.

But basically: PEO contains more or less constant percentage of oxygen (take a look at the formula). So if you take 1 mole of LiClO4 (and you have one mole of Li+) you need to find out what mass of PEO contains corresponding amount of oxygen (n-times higher, either in molar or mass proportion).
 
Hi Thankyou for your reply.

So PEO chemical formula is C2n H4n+2 On+1, which means, if the ratio of oxygen and lithium is 10 : 1, i have to insert n=9 in the PEO formula. which means the calculation of weight of the PEO becomes:
O9+1 = O10 = 10 mol x 16 g/mol = 160 gram
H4n+2 = 4(9) + 2 = 36+2 = 38 mol x 1.00794 g/mol = 38.30172 gram
C2n = 2x9 = 18 mol = 18 mol x 12.0107 g/mol = 216.1926 gram

Total Weight = 160 + 38.30172 + 216.1926 = 414.49432 gram

The molar mass of Liclo4 is 106.39 g/mol, so the weight ratio is

414.49432 : 106.39 = 3.89 : 1 ~ 4 : 1

am i right? looking forward to your answer!
 

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