arpon
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Suppose we have ##a \equiv 0 (mod~ m)##. And, ## a \equiv b (mod~ n)##. Is there any way to relate ##b## with ##m## and ##n## ?
The discussion focuses on the mathematical relationship between congruences, specifically how to relate the variable b with moduli m and n. It establishes that if a is congruent to 0 modulo m (a ≡ 0 (mod m)) and a is congruent to b modulo n (a ≡ b (mod n)), then a can be expressed as a = k1m and a = k2n + b. This leads to the conclusion that b can be derived from the values of m and n through the manipulation of these equations.
PREREQUISITESMathematicians, computer scientists, and students studying number theory or modular arithmetic who seek to deepen their understanding of congruences and their applications.
Your first equation is equivalent to a = k1m, and the second is equivalent to a = k2n + b.arpon said:Suppose we have ##a \equiv 0 (mod~ m)##. And, ## a \equiv b (mod~ n)##. Is there any way to relate ##b## with ##m## and ##n## ?