How to Cool 70°C Water to 35-38°C?

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SUMMARY

The discussion focuses on calculating the temperature needed to cool 3-4 ounces of water from 70°C to a target range of 35-38°C. The user initially attempted to mix the hot water with room temperature water (20-25°C) but achieved temperatures of 41°C and 46°C instead. The consensus is that a simple ratio calculation can be used, assuming no heat loss and perfect mixing, to determine the required temperature of the additional water. Specifically, to achieve the desired temperature, the user needs to add water at approximately 3-4°C.

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I have a question about how to cool the water that's already in my cup. I already have 3-4 ounces of 70°C water in my cup and want to bring that overall temperature down to 35-38°C. The end solution needs to have 8 ounces of water. I already tried doing this with room temperature water (20-25°C) and the end solution came out to be 41°C and 46°C in my two trials.

Is there a certain formula I can use to calculate the temperature needed to cool the 70°C water down to my desired range?
 
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Hi,

Is it as simple as a ratio , assuming there is no heat loss to the surroundings through the process and that the water is well mixed

if you have

4 ounces at 70
4 ounces at 20
you'll have 8 ounces at 45

by that logic you'd need water at about 3-4 degrees
 
Maxong091 said:
Hi,

Is it as simple as a ratio , assuming there is no heat loss to the surroundings through the process and that the water is well mixed

if you have

4 ounces at 70
4 ounces at 20
you'll have 8 ounces at 45

by that logic you'd need water at about 3-4 degrees

Great! Thank you! I knew it had to be a simple calculation, but didn't even think it'd be that simple!
 

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