How to correct (adjust) Amazon ratings based on the number of reviews

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  • Thread starter Thread starter Wes Turner
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SUMMARY

This discussion focuses on adjusting Amazon product ratings based on the number of reviews to provide a more accurate assessment of product quality. The user proposes using a Bayesian approach to calculate an adjusted rating, emphasizing the importance of a higher number of reviews for reliability. They also explore calculating confidence intervals using Excel's T-distribution and N-distribution functions for a 95% confidence level, seeking feedback on their methodology and potential alternatives.

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  • Understanding of Bayesian statistics
  • Familiarity with confidence intervals
  • Proficiency in Excel functions, specifically T-distribution and N-distribution
  • Basic knowledge of product rating systems
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  • Research Bayesian statistics for rating adjustments
  • Learn how to calculate confidence intervals in Excel
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Data analysts, e-commerce professionals, product managers, and anyone interested in improving the accuracy of product ratings based on review quantity.

Wes Turner
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I would like a way to compare Amazon ratings as a function of the number of reviews. I think it's pretty clear that a product with a 4.9 rating based of 5,000 reviews is likely better than one with a 5.0 rating based on just 1 review. But how can I calculate an adjusted rating for a set of products
such as the ones in this table of ratings and number of reviews.

1716078636487.png


Thanks
 
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Well, you could set a threshold and use a Bayesian approach to assess the posterior probability that the rating is higher than the threshold
 
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I don't know what that is or how to do it. Is there a formula I can put in the Adjusted Rating column?

I was thinking about calculating a confidence interval. Here's my first try at that. I calculated the confidence interval using the Excel T-distribution confidence interval function, then subtracted that from the rating.

I then did the same thing using the Excel N-distribution confidence interval function and subtracted that from the rating.

Here's the data for a 95% confidence interval. The last column shows the difference in the rankings from using an N-distribution function vs a T-distribution function.

1716085458200.png


Any comments? Is there a better way? Should I use a different confidence interval (97%? 99%?)?

Thanks
 

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