MATLAB How to create distinct circles in Matlab?

[jamalkoiyess]

I want to create a plate of distinct circles on Matlab where their radii are generated by randn(1,p) and centers are random. I am currently doing the circles using viscircles, but some of them are overlapping, and since I want approximately 100 ones, this problem only gets worse.
How can I make them so they are distinct? And if I want an average distance between them, how can I do it? (let's say 1 unit between one and the other)
Thank you!

 

[Nidum]

Use random numbers to generate a mesh of triangles .

In fill the triangles with circles .

You can use rules to control shape factors and relative sizes of triangles if you want to .

 

[jamalkoiyess]

Use random numbers to generate a mesh of triangles .

How can I do that? I am a total beginner at Matlab so can you please go a bit easy on me if you can. Thank you

 

[lewando]

I can't readily see how to do this with a triangular mesh (too early in the morning, perhaps). I can probably imagine how to do it with a simple rectangular grid, with each cell containing one circle of random radius and position. A test would have to be performed on x, y, and r to make sure is completely inside a cell. What I don't like about that approach is the reduction in randomness even though circles can be randomly located within a cell.

A more random approach might be this: maintain an Nx3 array, where each N index would contain x_N, y_N, and r_N. N could be exactly 100 which satisfies your "approximately 100" requirement. Placement of circle N=1 (C₁) is easy because there are no constraints. Placement of candidate circle C₂ would have to pass a test before it could be added to the array and placed on the field. You can compute the distance between x₁, y₁ and the new candidate location. If this distance is greater than the sum of r₁ and r_candidate, then you can add it to the array and place it on the field. For candidate circle C₃, it would have to pass the test against C₂ and C₁. And so on.

And if I want an average distance between them, how can I do it? (let's say 1 unit between one and the other)

If you want a specific average distance between the circles' edges, then this constraint in conflict with the random size and location constraint. I would ask you to provide the context that drives this necessity.

 

[Nidum]

 

[jamalkoiyess]

I can't readily see how to do this with a triangular mesh (too early in the morning, perhaps). I can probably imagine how to do it with a simple rectangular grid, with each cell containing one circle of random radius and position. A test would have to be performed on x, y, and r to make sure is completely inside a cell. What I don't like about that approach is the reduction in randomness even though circles can be randomly located within a cell.

A more random approach might be this: maintain an Nx3 array, where each N index would contain x_N, y_N, and r_N. N could be exactly 100 which satisfies your "approximately 100" requirement. Placement of circle N=1 (C₁) is easy because there are no constraints. Placement of candidate circle C₂ would have to pass a test before it could be added to the array and placed on the field. You can compute the distance between x₁, y₁ and the new candidate location. If this distance is greater than the sum of r₁ and r_candidate, then you can add it to the array and place it on the field. For candidate circle C₃, it would have to pass the test against C₂ and C₁. And so on.
If you want a specific average distance between the circles' edges, then this constraint in conflict with the random size and location constraint. I would ask you to provide the context that drives this necessity.

I did the random approach you suggested yesterday. I tested it on Java and took the arrays to matlab. It is working great. And I just abandoned the requirement for the average distance between cirlces.
Thank you.