How to derive a simple profit equation. Kinda embarrassing.

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The discussion focuses on creating a profit equation to determine the total price needed to achieve a specific profit after accounting for supplier costs and transaction fees. The user initially struggles with a brute force method to find the total price but seeks a mathematical solution instead. Through algebraic manipulation, they derive formulas for total price and transaction fee based on supplier cost and desired profit. The final equations allow for easy adjustments to the transaction fee percentage, making the calculator more versatile. The user expresses satisfaction with the solution and the understanding gained from the discussion.
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I made this excel file that is basically a calculator. It needs to create a Total price after fees, profit and supplier cost. Most profit margin calculators have you add a percentage for profit... this is not what I want. I have a hard dollar amount.

You must know that the entire transaction includes supplier cost, profit and fee. The fee is charged from the total of the Transaction. I do not want to brute force until I find a total price that equals 5 bucks in profit.

For instance...

Supplier Cost : $50
Profit I want to make : $5
10% Transaction Fee : ?
Total to charge : Some unknown without brute force.

Currently you put the Supplier cost and a GUESS of the Total price. And keep adjusting while watching your profit until it gets to $5 bucks.So here is an example...

Enter Supplier cost... ___$50___
Enter Profit to make... ___$5____

With this info I need it to spit out the total to charge so that the money left in the account is enough to
*pay supplier
*Pay transaction fee
*And exact profit of $5 is what is left.

In this case...
*Fee is: $6.11
*Total price is $61.11

Customer is charged 61.11 and we pay a transaction fee and a profit. It should zero out.Does this make sense?
 
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Have you tried algebra?

You know:

T = total price

X = transaction cost

F = transaction fee = 0.1 * X

F + X = T or 0.1 * X + X = T, which means

1.1 * X = T

X = T / 1.1

X = Cost + Profit = T / 1.1

So Profit = (Total Price / 1.1) - Cost

Something like this?
 
The problem is we have 2 unknowns: Transaction fee and Total Price.

Fee can be derived from Total Price.
Total price can be derived from Fee + Cost + Profit

We only have Cost and Profit

Basically, I could write a brute force method in Java, but I just think there is some math I do not understand. Probably because there is 2 missing variables. Fee and Total.Edit: I looked at your math and I am unsure it does what I am trying to do. Maybe I am missing something. Thank you.
 
AcousticBruce said:
Basically, I could write a brute force method in Java, but I just think there is some math I do not understand. Probably because there is 2 missing variables. Fee and Total.Edit: I looked at your math and I am unsure it does what I am trying to do. Maybe I am missing something. Thank you.

You have two variables, but you also have two equations that relate those variables.

S = supplier cost
P = profit to make
F = transaction fee
T = total price

So we have that

T = S+F+P

We know S and P, so they're constants, so we have two variables in that equation, T and F.
The other equation is:

0.1*T = F

So then if we plug 0.1*T for F into the first equation, then we get

T = S + 0.1*T + P

solving for T,

T - 0.1*T = S+P
(1-0.1)T = S+P
T = (S+P)/0.9

and then plugging this value for T back into the second equation, we get

0.1*(S+P)/0.9 = F

So your two results are

T = 10/9*(S+P)
F = 1/9*(S+P)

You can easily generalize this procedure so that you can use any % in your transaction fee that you wish.
 
Wonderful! Thank you both for the time and effort not only does this work, but I understand it completely. I also added a way to change the percentage on the calculator. Wonderful!
 
AcousticBruce said:
Wonderful! Thank you both for the time and effort not only does this work
Well of course it works, it's Math ;)

AcousticBruce said:
but I understand it completely. I also added a way to change the percentage on the calculator. Wonderful!
That's good to hear!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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