How to differentiate e^(x+y) for x?

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SUMMARY

The discussion focuses on differentiating the function f(x,y) = e^(x+y) with respect to x. It establishes that if y is not a function of x, the derivative dy/dx is undefined, except in the trivial case where dy/dx equals zero. The conversation highlights the importance of recognizing x and y as independent variables, allowing for the calculation of partial derivatives ∂f/∂x and ∂f/∂y. Additionally, it introduces implicit differentiation as a method to find dy/dx when f(x,y) is held constant.

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Homework Statement



if f(x,y) is e^(x+y) am i right in saying dy/dx is e^(x+y)


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The Attempt at a Solution

 
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If y is not a function of x, dy/dx makes no sense at all! (Except for dy/dx= 0.)
The notation f(x,y)= ex+y implies that x and y are independent variables. Without further information, you can find \partial f/\partial x or \partial f/\partial y but not dy/dx.

If, for example, you know that f(x,y)= ex+y= constant, then you can use "implicit differentiation": (1+ dy/dx)ex+y= 0 and determine that dy/dx= -1.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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