How to evaluate : ∫[(2-x)/(1-x^2)]dx.

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Discussion Overview

The discussion revolves around the evaluation of the integral ∫[(2-x)/(1-x^2)]dx. Participants explore methods for solving the integral, including the use of partial fractions and the importance of demonstrating prior work in the forum context.

Discussion Character

  • Homework-related
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant suggests separating the integral into two parts as a first step.
  • Another participant emphasizes the importance of politeness and prior effort in seeking help, criticizing the initial request for urgency.
  • Some participants advocate for the use of partial fractions to simplify the integral, proposing a specific form involving constants A and B.
  • A humorous remark referencing Britney Spears is made, possibly to lighten the tone of the discussion.

Areas of Agreement / Disagreement

There is a clear disagreement regarding the approach to the initial request for help, with some participants expressing frustration over the tone of the inquiry. However, there is a shared understanding among some that partial fraction decomposition is a valid method to approach the integral.

Contextual Notes

Participants have not reached a consensus on the best approach to the integral, and there are unresolved issues regarding the initial request for assistance and the expectations of forum etiquette.

kanika2217
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how to evaluate : ∫[(2-x)/(1-x^2)]dx...
pls ans me asap...its urgnt
 
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First step separate into two integrals.
 
Your attitude is completely out of bounds.
These forums are upheld by private individuals who use of their spare time to offer advice.

And how do you barge in here?

by DEMANDING answers "as soon as possible", because that is somehow "urgent" for yourself.

obviously, it has been SO urgent that you haven't done anything on your own, but demand to be handed over the answers.

Do you even understand how WAY out of line you behave?
 
arildno is quite right.
 
I agree with arildno. Be polite and show us what you have done yourself.

Now, to help you do it yourself, use "partial fractions". The denominator of your fraction, [itex]1- x^2[/itex] factors as (x- 1)(x+ 1). That means we can write
[tex]\frac{2- x}{1- x^2}= \frac{A}{x- 1}+ \frac{B}{x+ 1}[/tex]
for some numbers A and B. Can you find them?

Do you know how to integrate [itex]A/(x- 1)[/itex] and [itex]B/(x+ 1)[/itex]?
 
Britney Spears said "Whoops, I did it again!"
You ought to do as she did, HallsofIvy, with respect to the factorization..:smile:
 

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