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How to evaluate : ∫[(2-x)/(1-x^2)]dx.

  1. Nov 8, 2011 #1
    how to evaluate : ∫[(2-x)/(1-x^2)]dx.........
    pls ans me asap...its urgnt
     
  2. jcsd
  3. Nov 8, 2011 #2
    First step seperate into two integrals.
     
  4. Nov 8, 2011 #3

    arildno

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    Your attitude is completely out of bounds.
    These forums are upheld by private individuals who use of their spare time to offer advice.

    And how do you barge in here?

    by DEMANDING answers "as soon as possible", because that is somehow "urgent" for yourself.

    obviously, it has been SO urgent that you haven't done anything on your own, but demand to be handed over the answers.

    Do you even understand how WAY out of line you behave?
     
  5. Nov 8, 2011 #4
    arildno is quite right.
     
  6. Nov 8, 2011 #5

    HallsofIvy

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    I agree with arildno. Be polite and show us what you have done yourself.

    Now, to help you do it yourself, use "partial fractions". The denominator of your fraction, [itex]1- x^2[/itex] factors as (x- 1)(x+ 1). That means we can write
    [tex]\frac{2- x}{1- x^2}= \frac{A}{x- 1}+ \frac{B}{x+ 1}[/tex]
    for some numbers A and B. Can you find them?

    Do you know how to integrate [itex]A/(x- 1)[/itex] and [itex]B/(x+ 1)[/itex]?
     
  7. Nov 8, 2011 #6

    arildno

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    Britney Spears said "Whoops, I did it again!"
    You ought to do as she did, HallsofIvy, with respect to the factorization..:smile:
     
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