How to explain that ∇ ⋅ B = 0 but ∂Bz/∂z can be non zero?

  • Thread starter Thread starter Dyon
  • Start date Start date
  • Tags Tags
    Explain Zero
Click For Summary
Gauss's law for magnetism states that ∇ ⋅ B = 0, which means the sum of the partial derivatives of the magnetic field components must equal zero. In component form, this is expressed as (∂Bx/∂x) + (∂By/∂y) + (∂Bz/∂z) = 0, indicating that while the total must be zero, individual components can be non-zero. This is exemplified in scenarios like the Stern-Gerlach experiment, where ∂Bz/∂z can indeed be non-zero due to spatial gradients in the magnetic field. The key point is that the equation represents a scalar sum, allowing for individual derivatives to vary while maintaining the overall condition. Understanding this distinction clarifies the relationship between the divergence of B and the behavior of its components.
Dyon
Messages
29
Reaction score
2
It is known that Gauss's law for magnetism is ∇ ⋅ B = 0.
If we write this in component form it becomes (∂Bx/∂x)i + (∂By/∂y)j + (∂Bz/∂z)k = 0, where i, j, k are unit vectors in a cartesian coordinate system and Bx, By, Bz are the components of the magnetic field on these axes.
It would follow then that all the partial derivatives must be zero: (∂Bx/∂x) = 0, (∂By/∂y) = 0 and (∂Bz/∂z) = 0 for this equation [ (∂Bx/∂x)i + (∂By/∂y)j + (∂Bz/∂z)k = 0 ] to obtain.
But we know that there are magnetic fields with spatial gradients as, for example, in Stern-Gerlach experiment, where the magnetic force on a dipole of magnetic moment F is m⋅(∂Bz/∂z).
How to reconcile mathematically ∇ ⋅ B = 0 with the fact that ∂Bz/∂z can be non-zero?
Thank you.
 
Physics news on Phys.org
In component form ∇.B=0 reads,
∂Bx/∂x+∂By/∂y+∂Bz/∂z=0,there is no vector here because the product is scalar as implied by ∇.B
 
It's a dot product. That should tell you right away that the answer needs to be a scalar.

\nabla \cdot B = \frac{\partial B_x}{\partial x} + \frac{\partial B_y}{\partial y} + \frac{\partial B_z}{\partial z} = 0

Any of these can individually be non-zero. So long as the sum is zero.
 
Thank you, andrien and K^2. I completely overlooked that ∇ ⋅ B is regarded as a dot product.
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 16 ·
Replies
16
Views
6K
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
19
Views
3K