How to find a:b:c given that s-a:s-b:s-c = 1:2:3

[zorro]

Homework Statement

Let s-a : s-b : s-c :: 1:2:3

then how do we find a:b:c from this?

Homework Equations

The Attempt at a Solution

 

[Borek]

Try to format your expression in such a way that it is unambiguous what you are looking for.

 

[zorro]

How do I do that?

 

[Borek]

You may try to use LaTeX.

https://www.physicsforums.com/showthread.php?t=8997

 

[Mark44]

Homework Statement

Let s-a : s-b : s-c :: 1:2:3

then how do we find a:b:c from this?

Rewrite this proportion as three equations. The proportion is saying is that s - b is 2 times s - a, s - c is 3 times s - a, and s - c is (3/2) times s - b.

That should give you somewhere to start.

 

[zorro]

Thanks a lot

 

[HallsofIvy]

Homework Statement

Let s-a : s-b : s-c :: 1:2:3

then how do we find a:b:c from this?

Homework Equations

The Attempt at a Solution

That's slightly confusing because it represents several proportions together.
You can analyze it as $s-a: s-b::1:2$, $s-b: s-c::2: 3$, and [itex]s-a: s-c::1: 3[itex]. Those can be written as fraction:<br /> $$\frac{s-a}{s-b}= \frac{1}{2}$$<br /> $$\frac{s-b}{s-c}= \frac{2}{3}$$<br /> and<br /> $$\frac{s-a}{s-c}= \frac{1}{3}<br /> <br /> The first equation can be rewritten as 2(s- a)= s- b, 3(s-b)= 2(s- c), and 3(s-a)= s- c.<br /> <br /> You can solve each of those for s: 2s- 2a= x- b so s= 2a- b. 3s- 3b= 2s- 2c so s= 3b- 2c. 3s- 3a= s- c so 2s= 3a- c or s= (3/2)a- (1/2)c. <br /> <br /> Now put them back together: s= 2a- b= (2/3)a- (1/2 c, s= 2a- b= 3b- 2c. You should be able to find the relationships between a, b, and c from that.$$[/itex][/itex]

 

[zorro]

That's slightly confusing because it represents several proportions together.
You can analyze it as $s-a: s-b::1:2$, $s-b: s-c::2: 3$, and [itex]s-a: s-c::1: 3[itex]. Those can be written as fraction:<br /> $$\frac{s-a}{s-b}= \frac{1}{2}$$<br /> $$\frac{s-b}{s-c}= \frac{2}{3}$$<br /> and<br /> $$\frac{s-a}{s-c}= \frac{1}{3}<br /> <br /> The first equation can be rewritten as 2(s- a)= s- b, 3(s-b)= 2(s- c), and 3(s-a)= s- c.<br /> <br /> You can solve each of those for s: 2s- 2a= x- b so s= 2a- b. 3s- 3b= 2s- 2c so s= 3b- 2c. 3s- 3a= s- c so 2s= 3a- c or s= (3/2)a- (1/2)c. <br /> <br /> Now put them back together: s= 2a- b= (2/3)a- (1/2 c, s= 2a- b= 3b- 2c. You should be able to find the relationships between a, b, and c from that.$$[/itex][/itex]

[itex][itex]$$<br /> That made it more clear.<br /> I got a:b:c :: 5:4:3<br /> Thanks a lot Hallsofivy$$[/itex][/itex]