How to find a force at a different angle?

  • Thread starter Thread starter Kalookakoo
  • Start date Start date
  • Tags Tags
    Angle Force
Click For Summary

Homework Help Overview

The discussion revolves around determining the component of a force acting at point C that is perpendicular to the line CP. The original poster has provided specific force values and angles, indicating a focus on vector components and moments in a physics context.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of force components using angles and vector relationships. There are questions about how to find the perpendicular component of the force and the implications of drawing accurate diagrams.

Discussion Status

Participants are actively engaging with the problem, sharing diagrams and discussing their calculations. Some have expressed confusion about their results and the relationship between different methods of calculating moments, indicating a productive exploration of the topic.

Contextual Notes

There is mention of a specific angle and the need for accurate diagrams, suggesting that visual representation is crucial for understanding the relationships between the forces involved. Additionally, discrepancies in calculated moments indicate potential misunderstandings or errors in the approach taken.

Kalookakoo
Messages
25
Reaction score
0

Homework Statement


By finding angles, determine the component of the force acting at C which is perpendicular to the line CP. Show that the resulting moment agrees with the calculation in part (ii), if you were to look at that force alone.

Force at C = 200Ni + 250Nj (calculated to be at an angle 75.96 angle from x axis)
Force C magnitude = 320.156N



Homework Equations



Simple cos for x component and sin for y component, etc.



The Attempt at a Solution



This is part c of a problem. I have calculated that the line perpendicular to CP is 87.138 degrees off the x axis. So how do I find the component acting at that angle?

I feel like this is really easy and I'm just overthinking things.

I don't want the answer to the problem which is why I left out where the origin for the moment will be. I just want to know how to find this force.
 
Physics news on Phys.org
Kalookakoo said:

Homework Statement


By finding angles, determine the component of the force acting at C which is perpendicular to the line CP. Show that the resulting moment agrees with the calculation in part (ii), if you were to look at that force alone.

Force at C = 200Ni + 250Nj (calculated to be at an angle 75.96 angle from x axis)
Force C magnitude = 320.156N



Homework Equations



Simple cos for x component and sin for y component, etc.



The Attempt at a Solution



This is part c of a problem. I have calculated that the line perpendicular to CP is 87.138 degrees off the x axis. So how do I find the component acting at that angle?

I feel like this is really easy and I'm just overthinking things.

I don't want the answer to the problem which is why I left out where the origin for the moment will be. I just want to know how to find this force.

Have you drawn a reasonably accurate diagram?
 
Kalookakoo said:
Here's the diagram.

http://i.imgur.com/4yGeT.png

OK, that looks like the supplied diagram.

Have you added in any lines of your own - like the line CP, then the components of the force parallel and perpendicular to that line?

Once they are drawn, you should be able to calculate what you are after.
 
I have it drawn out but I'm stuck though it seems obvious...

I mean, it's just those 2 vectors with that theta in between. But you can't find the other magnitude with just one angle and one vector...

Or do the two connect at their tips to form a right angle of some sort?
 
Kalookakoo said:

Homework Statement


By finding angles, determine the component of the force acting at C which is perpendicular to the line CP. Show that the resulting moment agrees with the calculation in part (ii), if you were to look at that force alone.

Force at C = 200Ni + 250Nj (calculated to be at an angle 75.96 angle from x axis)
Force C magnitude = 320.156N



Homework Equations



Simple cos for x component and sin for y component, etc.



The Attempt at a Solution



This is part c of a problem. I have calculated that the line perpendicular to CP is 87.138 degrees off the x axis. So how do I find the component acting at that angle?

I feel like this is really easy and I'm just overthinking things.

I don't want the answer to the problem which is why I left out where the origin for the moment will be. I just want to know how to find this force.

Your statement in red, above, is true for finding the x- and y-components. You will be using the the etc part of the statement.

The Force vector forms some angle with the direction you seek - let's call it θ.

The value of the component will be either Fc.cosθ or Fc.sinθ

One of those values will be much bigger that the other.

If you have a carefully drawn diagram, you will be able to see if it is the perpendicular or parallel component that is bigger - thus you know which component is which.

Of course, if your diagram is so approximate that you draw the angles bearing little resemblance to their real values then you will be in great doubt about which one is which.
 
Ahh I see now. I have a bad habit of not drawing diagrams or not doing them well enough to scale. Thanks for the help.
 
And I got the wrong answer. My moments from that point using the two methods are not equal.

I found the moment using x and y components timers perpendicular distance is equal to 52000.

Using the second method, I found it to be 63879.

I feel like I did the first method fine.

For the second method I found the perpendicular angle to be 87.138 with a force magnitude of 319.7569N. The distance between point P and point C I found to be 200.2498m.

Are those numbers correct>
 
Bump?
 
  • #10
Supplying the whole question rather than the end parts makes us see the whole picture.
 

Similar threads

Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
1K
Replies
3
Views
1K
Replies
21
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
1K
Replies
3
Views
2K