- #1

grbd920

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**1. A ship is launched into the water down a ramp making an angle of 8 degrees with the horizontal. The coefficient of kinetic friction between the bottom of the ship and the ramp is μk=0.06. What is the acceleration of the ship down the ramp?**

**2. I know that the equation to solve this is**

a = gsin(theta) - μkgcos(theta)

Which gives you 0.8 m/s^2

a = gsin(theta) - μkgcos(theta)

Which gives you 0.8 m/s^2

**3. So, I have the equation to solve it and the correct answer but I'm just not sure how to derive that equation in the first place?**