How to find distance when a ball rolls slope with angle?

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SUMMARY

The discussion focuses on calculating the distance a steel ball travels when rolling down slopes of 35 degrees and 45 degrees. The ball rolls from heights of 0.5 m and 1 m, respectively, with the final velocity calculated as 3.74 m/s using the equation V=sqrt(10/7)xgh, where g=9.8 m/s². Participants emphasize the need to consider rotational energy in the calculations and suggest clarifying the physics class level for better context.

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Homework Statement


A) For a steel ball rolling down a 35 degree slope from a height of .5 m above the table, how far will the ball travel in the x direction if it launches horizontally from the table which is 1m high

For the same ball rolling down a 45 degree slope from one meter high, what maximum diameter of loop the loop will the ball go around without falling? Show work?

Homework Equations


a=v^2/r
V=sqtroot(10/7)xgh
g=9.8m/s

The Attempt at a Solution


I got V= 3.74m/s which seems pretty high/fast and then idk what else to do to find the distance. Any help would be great!
 
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physicsstudent101 said:

Homework Statement


A) For a steel ball rolling down a 35 degree slope from a height of .5 m above the table, how far will the ball travel in the x direction if it launches horizontally from the table which is 1m high
I think you need to show more of the details of your work so far. How did you find the final velocity? Do you need to take into account the rotational energy of the steel ball?

Perhaps you could tell us what physics class level this problem is aimed at?
 

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