The discussion centers on calculating the horizontal distance a ball will travel when launched at a 30-degree angle from a height of 56.2 meters. The key equation used is t = vy/g, where g is the acceleration due to gravity (9.8 m/s²). Participants clarify that dy represents the height of launch, leading to the conclusion that if dy is the maximum height, additional information is required to determine the landing distance accurately. The ambiguity around the definition of dy is critical for solving the problem correctly.
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Heck, I can't figure out what dy = 56.2 is supposed to be. Does it have units? Is it a velocity? A distance? What?lkadfj said:Homework Statement
A ball is launched at 30 degrees. How far away will it land if dy= 56.2
Homework Equations
t=vy/g
The Attempt at a Solution
t=vy/9.8m/s
I can't figure out how to find either vy or t
You seem to be saying that dy is the height from which it was launched (compared with the landing point, presumably). But if so, there's not enough information. From the name 'dy' I would guess it might mean the maximum height reached (as in, delta y), and that the landing point is on the same level as the launch point. If so, there is enough information.lkadfj said:A ball is launched at 30 degrees. How far away will it land if dy= 56.2m (height of launch)