MHB How to find equation from given data?

  • Thread starter Thread starter tantrik
  • Start date Start date
  • Tags Tags
    Data
Click For Summary
The discussion addresses how to derive cost equations for two mobile phone pricing plans. For Plan A, the cost equation is C = 15 + (0.25)t, where C is the total cost in dollars and t is the call time in minutes. For Plan B, the equation is C = 100 + (0.14)t. The calculations involve converting call rates from cents to dollars by dividing by 100. The thread concludes with appreciation for the provided solutions.
tantrik
Messages
13
Reaction score
0
Dear friends,

I am unable to solve the following problem. Will appreciate your help here. Thanks in advance.

The Purple Mobile Phone Company offers the following two pricing plans to customers. Plan A costs \$15/month, with calls at 25c/minute, while Plan B costs \$100/month with calls at 14c/minute. Find an equation that gives C, the cost in dollars, in terms of t, the call time in minutes per month for each plan.
 
Mathematics news on Phys.org
tantrik said:
Dear friends,

I am unable to solve the following problem. Will appreciate your help here. Thanks in advance.

The Purple Mobile Phone Company offers the following two pricing plans to customers. Plan A costs \$15/month, with calls at 25c/minute, while Plan B costs \$100/month with calls at 14c/minute. Find an equation that gives C, the cost in dollars, in terms of t, the call time in minutes per month for each plan.
You are given t in minutes and want to get C in dollars. There is a "cents/minute" so multiplying by t in minutes will result in cents. Dividing that by 100 cents/dollar will put it into dollars. The monthly cost is already in dollars so you can just add that:
C= 15+ (25/100)t

C= 100+ (14/100)t.
 
HallsofIvy said:
You are given t in minutes and want to get C in dollars. There is a "cents/minute" so multiplying by t in minutes will result in cents. Dividing that by 100 cents/dollar will put it into dollars. The monthly cost is already in dollars so you can just add that:
C= 15+ (25/100)t

C= 100+ (14/100)t.

Thanks for your explanation and working for the problem.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
2K
Replies
2
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
2K