How to Find the Path Function and Meeting Time for Three Moving Particles?

Click For Summary

Homework Help Overview

The discussion revolves around determining the path function and meeting time for three particles moving in an equilateral triangle configuration. The original poster attempts to analyze the velocity of one particle relative to another while considering the effects of a rotating frame of reference.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the concept of relative velocity and the implications of using a rotating frame of reference. There are inquiries about the speed of one particle towards another and the angles involved in their motion. Some participants suggest resolving vectors into components and using polar coordinates for clarity.

Discussion Status

The discussion is ongoing, with various participants providing insights and prompting further exploration of the problem. There is a focus on understanding the geometry and dynamics of the system, with no explicit consensus reached yet.

Contextual Notes

Participants note the absence of a clear diagram and the need for mathematical clarity in the problem statement. The discussion also highlights the challenge of interpreting the motion of the particles without complete information on their velocities and angles.

Crystal037
Messages
167
Reaction score
7
Homework Statement
At the corners if an equilateral triangle of side 'l', 3 particles A, B and C are located as shown. At t=0, all the particles start moving with a uniform speed v in such a manner that always velocity of A is heading towards B, B is heading towards C and C is heading towards A. Find the time after which 3 particles will meet
Relevant Equations
V(A-B) =V(A) - V(B)
Velocity of B wrt C =
(v +v*cos 60) i^ - vsin60 j^
= (3v/2)i^-((3)^(1/2)/2v)j^
But since C is also moving this initial velocity would vary. So how to find a function which defines its path and hence I can find time at which the particles meet. I was told to take rotating frame of reference that would rotate with a magnitude and direction of vsin(theta). That would cancel the (3)^(1/2)/2*v component. But I don't understand how a rotating frame which will cause some pseudo forces to cat on the system would cancel the component perpendicular to the line joining B and C. Please explain
.
 
Physics news on Phys.org
How fast is A approaching the centre?
 
  • Like
Likes   Reactions: jbriggs444
At the corners if an equilateral triangle of side 'l', 3 particles A, B and C are located as shown.

Where is the figure? Also, please write and explain your problem clearly using the mathematics tool available here, similar to ##\LaTeX##. As it stands, I understand very little of the problem you just asked, though it might well be an interesting one.
 
haruspex said:
How fast is A approaching the centre?
That is not given. Only the speed of A towards B is given.
 
brotherbobby said:
Where is the figure? Also, please write and explain your problem clearly using the mathematics tool available here, similar to ##\LaTeX##. As it stands, I understand very little of the problem you just asked, though it might well be an interesting one.
The figure is just an equilateral triangle and A, B and C are situated at its corners respectively.
 
Crystal037 said:
That is not given. Only the speed of A towards B is given.
What is the speed of A towards B ?
 
SammyS said:
What is the speed of A towards B ?
That's given in the problem statement:
Crystal037 said:
At t=0, all the particles start moving with a uniform speed v...
Moreover, we also know the direction (relative to the rotating frame). That gives us pretty much everything we need to solve the problem.
 
jbriggs444 said:
That's given in the problem statement:

Moreover, we also know the direction (relative to the rotating frame). That gives us pretty much everything we need to solve the problem.
What equations are you taking into considerations. Please elaborate.
 
Crystal037 said:
What equations are you taking into considerations. Please elaborate.
The one that @haruspex is trying to get you to think about in #2.
 
  • #10
jbriggs444 said:
The one that @haruspex is trying to get you to think about in #2.
How will I get that information. I only know how fast its approaching the other particles.
 
  • #11
Crystal037 said:
How will I get that information. I only know how fast its approaching the other particles.
What angle is it moving at? Measure that relative to a line pointed at the center of the triangle.

Edit: If you had listened to @brotherbobby in #3, you'd have a diagram ready to help.
 
  • #12
jbriggs444 said:
What angle is it moving at? Measure that relative to a line pointed at the center of the triangle.

Edit: If you had listened to @brotherbobby in #3, you'd have a diagram ready to help.
IMG_20200403_141427.jpg
 
  • #13
Crystal037 said:
Mark the centre of the triangle.
Do you know how to resolve vectors into components?
 
  • #14
Rotate that image.
EquiTri-IMG_20200403_141427.jpg


So, that's a lower case L representing the initial length of each side. That ##l## doesn't show well in the default PF sans-serif font. The UNICODE character for the script version, ℓ , does look better, but can be hard to find. (See the last letter in my signature.)

Find the center of the triangle, as @haruspex suggested, then, for any vertex, find the components of the velocity relative to the center.

In my opinion, it will also be helpful to use polar coordinates. For this, vertex A is simpler to work with. Get expressions for both the position and the velocity with respect to the center.
 
  • Like
Likes   Reactions: jbriggs444
  • #15
Personally, I find that starting with some simple observations about the symmetry of the system and how it must evolve over time eliminates the need for coordinates. But if you must use them, then polar coordinates are definitely nice here.
 
  • Like
Likes   Reactions: SammyS

Similar threads

Replies
20
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 40 ·
2
Replies
40
Views
3K
Replies
16
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K