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How to find the resultant of 3d vector?

  1. Jul 29, 2010 #1
    i have a vector ai+bj+ck

    is the resultant equal to sqrt(a^2+b^2+c^2). if so how do i explain it mathematically?

    i know the resultant of a 2d vector is equal to sqrt(a^2+b^2) and it can be proved from pythagoras theorem? any ideas??
  2. jcsd
  3. Jul 29, 2010 #2
    That is not resultant that is intensity. Yes if you have vector [tex]\vec{A}[/tex] then

  4. Jul 29, 2010 #3
    first of all, when u say u have a vector ai+bj, sqrt(a^2+b^2) gives u the magnitude of the vector, u shouldn't call it "resultant" as such,
    as far as a 3d vector is concerned u can find its magnitude using Pythagoras theorem only..

    Imagine the vector (a line with the arrow mark) ai+bj+ck, in a xyz space. Then imagine u have drawn a plane consisting the vector and perpendicular to the xy plane, then u can think of a rt triangle OAB being formed with co-ordinates, O(0,0,0); A(a,b,0); and B(a,b,c). The height of the rt triangle is 'b', and its base length is nothing but sqrt(a^2+b^2),[by distance formula]. therefore the length of the hypotenuse of the triangle OAB is sqrt(a^2+b^2+^c).

    this is the magnitude of ur vector ai+bj+ck!!!!!!!!

    i hope u got it!
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