How to Find the Velocity Components After 10 Seconds?

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SUMMARY

The discussion focuses on calculating the velocity components of an object subjected to three forces: F1=(-2.00i + 2.00j)N, F2=(5.00i - 3.00j)N, and F3=(-45.0i)N, resulting in an acceleration of 3.75 m/s². The mass of the object can be determined using Newton's second law, F=ma, leading to a mass of 12 kg. After 10 seconds of constant acceleration from rest, the object's speed can be calculated using the formula V = at, yielding a final speed of 37.5 m/s. The velocity components after 10 seconds are derived from the direction of the acceleration and the initial conditions.

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Ayesh
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Three forces acting on an objetc are given by F1=(-2.00i + 2.00j)N, F2=(5.00i - 3.00j)N, F3=(-45.0i)N The object experiences an acceleration of magnitude 3.75 m/s2.
a) What is the direction of the accceleration?
b) What is the mass of the object?
c) If the object is initially at rest, what is its speed after 10.0s?
d) What are the velocity components of the object after 10.0s?



The only I'm unable to do is d).
Can someone give me some hints to do it please?
 
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Velocity and Acceleration are vectors; time is a scalar unit. If, for constant acceleration, V = at, what's the direction of the velocity?
 
I don't see how it will help me find the velocity in y and x.
 

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