How to Find Values of k for Equations with One Real Root?

[mathdad]

Find values of k such that the equation has exactly one real root.

1. 3x^2 + (sqrt{2k})x + 6 = 0

2. kx^2 + kx + 1 = 0

Question:

Do the questions above involve the discriminant?

If so, I must apply b^2 - 4ac = 0, right?

 

[kaliprasad]

Find values of k such that the equation has exactly one real root.

1. 3x^2 + (sqrt{2k})x + 6 = 0

2. kx^2 + kx + 1 = 0

Question:

Do the questions above involve the discriminant?

If so, I must apply b^2 - 4ac = 0, right?

Yes . you can solve with discriminant and you must apply $b^2-4ac=0$

 

[mathdad]

Not too bad.