Find Y(s)/X(s) for y(t) = u(t - a).x(t)

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SUMMARY

The discussion centers on finding the ratio Y(s)/X(s) for the function y(t) = u(t - a) . x(t), where u(t) is a unit step function. Participants confirm that Y(s) and X(s) represent the Laplace transforms of y(t) and x(t), respectively. The correct transformation is established as Y(s) = e^(-as)X(s), indicating the relationship between the time-shifted function and its Laplace transform. A reference to an article suggesting Y(s) = e^(-as) . Laplace{x(t + a)} is also noted, but the consensus supports the direct calculation method.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with unit step functions and their role in signal processing
  • Knowledge of time-shifting properties in the Laplace domain
  • Basic concepts of convolution in the frequency domain
NEXT STEPS
  • Study the properties of Laplace transforms, focusing on time-shifting
  • Explore convolution in the frequency domain and its applications
  • Review examples of unit step functions in signal processing
  • Investigate the relationship between time-domain functions and their Laplace transforms
USEFUL FOR

Students and professionals in engineering, particularly those specializing in control systems, signal processing, and applied mathematics, will benefit from this discussion.

Debdut
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y(t) = u(t - a) . x(t)
u(t) is a unit step function. I have to find Y(s)/X(s). Do I have to do convolution in frequency domain?
 
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First, are we to assume that "X(s)" and "Y(s)" are the Laplace transforms of x(t) and y(t)? I don't see any reason why you just cannot calculate directly that the Laplace transform of y(t) is e^{-s}X(s) or get it from a table of transforms.
 
Thanks for the quick reply.
Do you mean e-asX(s). But that is the laplace of x(t - a).
Am I wrong?
 
Found an article where they're saying Y(s) should be Y(s) = e-as . Laplace{x(t + a)}
 

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