Chemistry How to get molality without using a molecular formula?

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To calculate the molality of acetone without using its molecular formula, the freezing point depression equation, ΔTf = mkf, can be utilized. The student has determined a freezing point change of 4°C and knows the mass of the solution is 90.4g, which is 0.904kg. By rearranging the equation to solve for molality (m), the number of moles of solute can be derived from the known freezing point depression and the solvent's freezing point constant (kf). The mass percentage of acetone, 12.28%, can also provide additional context for the calculations. Ultimately, the molality can be calculated using the provided data and equations.
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Homework Statement


Freezing point depression question[/B]
student determines molar mass of acetone using the method used in this experiment. She found that the eq temp of water and ice was 1 deg C. She then adds 11.1g of the sample to mixture and temp falls to -3 deg C. Mass of solution was 90.4g
What is the molality of the acetone using the experimental data and equation delta T_f = mk_f?

Homework Equations


Im lost on how to get moles without using the MM from formula for acetone?

The Attempt at a Solution


I know that T_f = 4deg C
also that m = moles solute / kg solvent
Also (if this is useful) that mass % = 12.28% acetone
also that kg of the solution will be = .904kg
thanks for any help
 
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You know ΔTf, you know (or can look up) kf, so you can work out m. If you also know the MW of acetone, you can check how accurate this m value is.
 

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