How to integrate y'/y=3 to find y=Ce^(3x)

[TravisUHEng]

Find the set of all solutions of the following differential equation

dy/dx=3y

I've gotten this far

y'=3y

y'/y=3

I feel like I'm forgetting a fundamental integration identity like,

y=ln(y'/y) <-- Not sure that is even correct.

I'm not sure. The book says the solution is y=Ce^3x. It makes sense, I'm just stuck somewhere between start and finish.

Any help?

Thanks,
Travis

 

[TravisUHEng]

Solved it. Thanks.