3(2k+1)3 I have written a program which calculates the value of that polynomial with different values of k. The result is always an odd number. I am having a difficult time writing a proof that states that this polynomial always returns an odd number. I know that (2k + 1) is the general form for odd numbers. My polynomial does have (2k+1) in it, but it is altered. Here are two different polymorphs of the same polynomial. They are just simplified versions: 3(8k3 + 12k2 + 6k + 1) 24k3 + 36k2 + 18k + 3 How can I prove that this is always odd?