How to Make a 0.3 M Sucrose Solution in the Lab?

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SUMMARY

To prepare a 500 mL solution of 0.3 M sucrose (C12H22O11), one must first calculate the required mass of sucrose using the formula: mass (g) = molarity (mol/L) × volume (L) × molar mass (g/mol). The molar mass of sucrose is 342.3 g/mol, thus 0.3 M requires 51.345 g of sucrose. Dissolve this mass in enough distilled water to reach a final volume of 500 mL. This method ensures accurate preparation of the desired molarity.

PREREQUISITES
  • Understanding of molarity and its calculation
  • Knowledge of the molar mass of sucrose (342.3 g/mol)
  • Familiarity with laboratory equipment for measuring liquids
  • Basic skills in solution preparation techniques
NEXT STEPS
  • Research the concept of molarity and its applications in laboratory settings
  • Learn about the properties and uses of sucrose in various experiments
  • Explore techniques for accurately measuring and mixing solutions
  • Investigate common laboratory safety protocols when handling chemicals
USEFUL FOR

Students in chemistry courses, laboratory technicians, and anyone involved in solution preparation and chemical experimentation.

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Homework Statement


Explain the steps you would follow to make 500 mL of a 0.3 M solution of sucrose (C12H22O11) in the lab.

I am not sure where to begin with this problem. Any assistance would be much appreciated.
 
Physics news on Phys.org
What does the M stand for?
 
molar concentration
 
what is the definition of a mole and molar concentration?
 
i figured it out myself.
 

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