C/C++ How to Properly Resize and Populate a Vector in C++ Without Using push_back?

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To resize the vector `countDown` to contain `newSize` elements and populate it with integers from `newSize` down to 1 without using `push_back`, the discussion highlights two methods for pre-allocating memory. The first method involves using `countDown.resize(newSize)`, which adjusts the size of the vector to `newSize`. The second method is to re-create the vector with `countDown = vector<int>(newSize)`. After resizing, the vector needs to be filled with the appropriate integers. The sample program is designed to output the countdown sequence followed by "Go!" when executed correctly.
EvanET
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Resize vector countDown to have newSize elements. Populate the vector with integers {newSize, newSize - 1, ..., 1}. Ex: If newSize = 3, then countDown = {3, 2, 1}, and the sample program outputs:

3 2 1 Go!

**I want to do this WITHOUT push_back**
#include <iostream>
#include <vector>
using namespace std;

int main() {
vector<int> countDown(0);
int newSize = 0;
int i = 0;

newSize = 3;

//enter code here

for (i = 0; i < newSize; ++i) {
cout << countDown.at(i) << " ";
}
cout << "Go!" << endl;

return 0;
}
 
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EvanET said:
Resize vector countDown to have newSize elements. Populate the vector with integers {newSize, newSize - 1, ..., 1}. Ex: If newSize = 3, then countDown = {3, 2, 1}, and the sample program outputs:

3 2 1 Go!

**I want to do this WITHOUT push_back**
#include <iostream>
#include <vector>
using namespace std;

int main() {
vector<int> countDown(0);
int newSize = 0;
int i = 0;

newSize = 3;

//enter code here

for (i = 0; i < newSize; ++i) {
cout << countDown.at(i) << " ";
}
cout << "Go!" << endl;

return 0;
}

Hi EvanET! Welcome to MHB! ;)

To pre-allocate the required memory, we can use 2 methods:
1. Call [M]countDown.resize(newSize)[/M].
2. Re-create the vector by executing [M]countDown = vector<int>(newSize)[/M].

After that we still have to fill in the newly available memory locations.
 
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