How to prove that line segment BF=tan x.tan y?

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Homework Help Overview

The discussion revolves around proving the relationship between line segment BF and the tangent functions of angles x and y, within the context of similar triangles. Participants are exploring geometric properties and relationships between the segments involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning how to estimate segments BD and BF, and discussing the implications of triangle similarity. There are attempts to clarify the use of mathematical symbols and to express BF in terms of angles x and y.

Discussion Status

The discussion is active, with participants providing insights into triangle similarity and proportionality. Some guidance has been offered regarding setting up proportions, while others are exploring different expressions for the tangents of the angles involved.

Contextual Notes

There is a mention of potential confusion regarding the use of mathematical notation, specifically the distinction between "implies" and "equals." Participants are also navigating the requirement to find specific expressions without making estimations.

Kamalesh
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Homework Statement
I came across a problem in geometry I don't know how to prove BF so please help me ?
Relevant Equations
Prove BF =tan x.tan y
IMG_20190919_101640640.jpg
 

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Hello.
How do you estimate BD? Then how do you estimate BF by BD?
 
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mitochan said:
How do you estimate BD? Then how do you estimate BF by BD?
The problem doesn't require any estimation.

@Kamalesh, in your work you have several lines such as "##BD \Rightarrow \tan y##" and others. The arrow symbol means "implies." You should be using "equals" (=) instead.

Triangles ABC and BDF are similar triangles, which means that their corresponding sides are proportional. In this case side BC in the left triangle corresponds to side BF in the right triangle. Set up a proportion using these two sides and two other corresponding sides of the triangles, and the result pops out quickly
 
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Observe ##\mathrm{DBF}##, it looks like you can express ##\mathrm{BF}## as a function of ##x##.
The problem here is that you went and found an expression for everything except what you're looking, ##\mathrm{BF}## that is.
 
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Find expressions for tan(x) and tan(y) and simply multiply them.
 
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