- #1
KRiBaH
- 3
- 0
Hello! I am new here! And i really like this site! So here's is my problem:
Well i know how to solve a simple equation with 2 incognites like:
x+y=2
x+4=2y
So in this case i do a substitue y=x-2 and use it in the second equation and it would be like:
x+4=2(x-2)
But the problem is if they only give me one equation with 2 incognites how can i solve it?
Example:
3x-4y+2=2(x+1)
Thanks!
Well i know how to solve a simple equation with 2 incognites like:
x+y=2
x+4=2y
So in this case i do a substitue y=x-2 and use it in the second equation and it would be like:
x+4=2(x-2)
But the problem is if they only give me one equation with 2 incognites how can i solve it?
Example:
3x-4y+2=2(x+1)
Thanks!