How to Solve a Quadratic Inequality with Two Variables?

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SUMMARY

The discussion focuses on solving the quadratic inequality -1 < 2x² - x < 1. The solution involves transforming the inequality into two separate inequalities: 0 < 2x² - x + 1 and 2x² - x + 1 < 2. The final solution is determined to be -1/2 < x < 1, confirmed through graphical analysis of the function y = 2x² - x. This method simplifies the problem and clarifies the solution set.

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Homework Statement



-1<2x[itex]^{2}[/itex]-x<1

Homework Equations





The Attempt at a Solution



I can't seem to solve this.. I am in calculus but I get to this point at the end of a long question, and it seems so trivial that I didn't think it would be a good idea to post this in the calculus forum.

How do you solve this? I know (from wolframalpha) that the answer is -1/2<x<1 but I don't know how it got this.
 
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skyturnred said:

Homework Statement



-1<2x[itex]^{2}[/itex]-x<1

Homework Equations





The Attempt at a Solution



I can't seem to solve this.. I am in calculus but I get to this point at the end of a long question, and it seems so trivial that I didn't think it would be a good idea to post this in the calculus forum.

How do you solve this? I know (from wolframalpha) that the answer is -1/2<x<1 but I don't know how it got this.
The inequality is equivalent to
0 < 2x2 - x + 1 < 2,
which is the same as these two inequalities:
0 < 2x2 - x + 1 AND 2x2 - x + 1 < 2

Do you know how to solve these quadratic inequalities?

Graphically, the solution set to your inequality is the set of x values on the graph of y = 2x2 - x for which -1 < y < 1.
 
Mark44 said:
The inequality is equivalent to
0 < 2x2 - x + 1 < 2,
which is the same as these two inequalities:
0 < 2x2 - x + 1 AND 2x2 - x + 1 < 2

Do you know how to solve these quadratic inequalities?

Graphically, the solution set to your inequality is the set of x values on the graph of y = 2x2 - x for which -1 < y < 1.

OK thanks! Splitting it up into two inequalities really makes it much easier to think about.
 

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