Doubt solving a polynomial inequality

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Homework Help Overview

The discussion revolves around solving a polynomial inequality involving a square root and a linear expression. The original poster expresses confusion regarding the positivity of the function and the implications of squaring both sides of the inequality.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to manipulate the inequality by rewriting it and questions the validity of their approach, particularly regarding the squaring of both sides. They also explore the implications of absolute values in their reasoning.
  • Some participants suggest analyzing the conditions under which the square root is defined and the behavior of the functions involved in different intervals.
  • Others raise concerns about the validity of squaring inequalities and discuss the conditions under which this operation is permissible.

Discussion Status

The discussion is active, with participants providing insights into the conditions necessary for squaring inequalities and exploring different cases for the variable x. There is a focus on clarifying misconceptions about the squaring process and its effects on the inequality.

Contextual Notes

Participants note the importance of considering the domain of the square root function and the implications of the variable's sign on the inequality. There is an acknowledgment of potential pitfalls in manipulating inequalities, particularly when squaring both sides.

greg_rack
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Homework Statement
$$\sqrt{x^{2}-2x}-x+1>0$$
Relevant Equations
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I got this function in a function analysis and got confused on how to solve its positivity;
I rewrote it as:
$$\sqrt{x^{2}-2x}>x-1 \rightarrow x^2-2x>x^2-2x+1$$
And therefore concluded it must've been impossible... but I'm certainly missing something stupid, since plotting the graphs of the two functions(##\sqrt{x^{2}-2x}## and ##x-1##) I see that the first is greater only for ##x<0##.

Maybe the flaw comes when I'm squaring both factors in the inequality... should I put the first factor in an absolute value, since it must be positive, as a square root?
But then, how do I solve it with the abs.?
I can deduce that the left term must be greater until the second term is negative... and for positive values it's the reversed situation, and this thinking works, but is there a more "rigid" procedure?
 
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You need to study the various part this inequality have.

First, x<0 or x>2 is a condition to the root.

So in the case x<0 the inequality is immediate, since the root is always greater than zero, and x-1 is zero

Now you apply for x>2 too.

Take the union.
 
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Your mistake is in the squaring, squaring inequalities just doesn't work sometimes. For example take the inequality -2<1 which is true. If you square it however you get the inequality 4<1 which is false..
 
Delta2 said:
Your mistake is in the squaring, squaring inequalities just doesn't work sometimes. For example take the inequality -2<1 which is true. If you square it however you get the inequality 4<1 which is false..
So, generally, you don't square inequalities? Is there a rule to avoid this type of mistakes?
 
I think the rule about squaring inequalities is that:

if both sides are positive then you can square it and the inequality keeps its direction

if both sides are negative then the inequality reverses direction after the squaring,

and if one side is negative and one positive then squaring is unpredictable!
 
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