You have sketched the arm in the correct quadrant. As for the principal angle, you are correct, however I would write:
$$\theta=\pi-\left(\tan^{-1}\left(-\frac{5}{2}\right)+\pi\right)=\tan^{-1}\left(\frac{5}{2}\right)$$
It appears you are to find the values of the primary trigonometric functions of the angle subtended by the arm and the positive $x$-axis. So, you want to use the angle:
$$\beta=\pi-\theta$$
And recall:
$$\sin(\beta)=\sin(\theta)$$
$$\cos(\beta)=-\cos(\theta)$$
$$\tan(\beta)=-\tan(\theta)$$
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