How to Solve an Introductory Momentum Problem Using Impulse?

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SUMMARY

The discussion focuses on solving a physics problem involving momentum and impulse. A 2.0 kg body traveling at 40 m/s East experiences a constant force of 10 Newtons East for 5 seconds. The final speed is calculated using Newton's Second Law, resulting in a final velocity of 65 m/s. The impulse-momentum theory is also highlighted as an effective method for solving such problems, emphasizing its relevance in understanding momentum concepts.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Familiarity with kinematic equations
  • Knowledge of impulse-momentum theory
  • Basic concepts of force and acceleration
NEXT STEPS
  • Study the derivation of Newton's Second Law in detail
  • Learn how to apply kinematic equations in various scenarios
  • Explore the impulse-momentum theorem and its applications
  • Practice solving momentum problems with varying forces and masses
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for effective methods to teach momentum and impulse concepts.

majormuss
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Homework Statement



Can someone help me solve this Physics question(about momentum)...?
A 2.0 Kg body is initially traveling at a velocity of 40 meters/sec East, If a constant force of 10 Newtons due East is applied to the body for 5 seconds , the final speed the body is?

Homework Equations


Am not sure


The Attempt at a Solution


My own answer to this question was 65m/s... I manipulated Newton's second law...a=F/mass,,, and I got ...v2(final velocity) = Ft/m- v1. Pls explain if your answer is different.
 
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That's correct!
Applying a constant force [tex]\vec F[/tex] on a body of mass [tex]m[/tex] provides that mass with an acceleration given by Newton's Second Law: [tex]\vec a = \frac{\vec F}{m}[/tex]
And from there, you can just use kinematics to find the final velocity.

A second, equivalent approach would be to use the impulse-momentum theory.
That is, [tex]\int \vec F dt=\vec P_f -\vec P_i[/tex]
 
Just want to add, if your class is studying momentum right now then it would be beneficial to solve this problem using the impulse formula. It is likely that the goal of this exercise is to give you practice using impulse in calculations.
 

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