How to solve delay differential equation

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SUMMARY

The discussion focuses on solving delay differential equations, specifically the equation \(\frac{1}{\omega} \frac{dV_0(t)}{dt} = V_i(t) - \frac{V_o(t-T_d)}{k}\), where \(T_d\) represents the delay. The participants confirm that the equation is linear, making Laplace transforms an appropriate method for finding a solution. The Laplace transform is defined as \(\mathcal{L}[f(t)] = \int_0^\infty e^{-st} f(t)\,dt = F(s)\), and the discussion also highlights the use of the shifted function property of Laplace transforms, \(\mathcal{L}[f(t - t_0)] = e^{-st_0} \int_{-t_0}^0 e^{-su} f(u)\,du + \mathcal{L}[f(t)]\).

PREREQUISITES
  • Understanding of delay differential equations
  • Familiarity with Laplace transforms
  • Knowledge of linear differential equations
  • Basic calculus skills
NEXT STEPS
  • Study the application of Laplace transforms in solving linear differential equations
  • Explore the properties of Laplace transforms, particularly the shifting theorem
  • Learn about numerical methods for solving delay differential equations
  • Investigate specific software tools for simulating delay differential equations, such as MATLAB or Mathematica
USEFUL FOR

Mathematicians, engineers, and researchers working with dynamic systems that involve time delays, particularly those interested in the analytical and numerical solutions of delay differential equations.

iVenky
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Is there some systematic procedure to solve delay differential equation ?

Here's one equation that I would like to solve

[itex]\large \frac{1}{ \omega } \frac{dV_0(t)}{dt} = V_i(t) - \frac{V_o(t-T_d)}{k}[/itex]

where
Td is the delay

Thanks
 
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iVenky said:
Is there some systematic procedure to solve delay differential equation ?

Here's one equation that I would like to solve

[itex]\large \frac{1}{ \omega } \frac{dV_0(t)}{dt} = V_i(t) - \frac{V_o(t-T_d)}{k}[/itex]

where
Td is the delay

Thanks

The equation is linear, so Laplace transforms are suitable:
[tex] \mathcal{L}[f(t)] = \int_0^\infty e^{-st} f(t)\,dt = F(s)[/tex]
You will need to use
[tex] \mathcal{L}[f(t - t_0)] = e^{-st_0} \int_{-t_0}^0 e^{-su} f(u)\,du + \mathcal{L}[f(t)][/tex]
 

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