How to Solve Modulus for x+2: -5<x<1

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Homework Help Overview

The discussion revolves around solving inequalities involving modulus functions, specifically the inequality |x+2| - 1 < 2. Participants are exploring the correct application of modulus properties and addressing confusion regarding their calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply a formula for modulus inequalities but questions their reasoning after receiving feedback on a miscalculation. Another participant suggests breaking down a different inequality, |x+2| < 3|x|, into cases based on the value of x.

Discussion Status

Participants are actively engaging with the problem, with some providing corrections and others proposing methods for approaching related inequalities. There is a recognition of confusion and a willingness to clarify misunderstandings.

Contextual Notes

The original poster expresses frustration with the complexity of the problem and mentions a preference for simpler methods over more extensive calculations, indicating a possible constraint in their approach to solving inequalities.

essaichay
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Hi everyone,

Ok I'm trying to revise modulus functions etc and this is supposed to be an 'easy' question but I came up with the wrong answer so now I'm getting confused.

I have to solve |x+2| - 1 <2

I used the formula: |x| < b <------> -b < x < b

And this is how I used it:

|x + 2| - 1<2
|x + 2|<3
-3< x + 2 <3
-1< x <5

Which is supposedly wrong because in the answer booklet it gives the solution: -5< x<1

AHH I'm so confused, sorry. I don't know if there's supposed to be another formula or something. My teacher taught us the squaring way but to be honest, in exams that just provides me with loads of working out to do which is tiring.

Thanks in advance to anyone who can help me on this!
 
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You added 2 instead of subtracting in the last step.
 
Vid said:
You added 2 instead of subtracting in the last step.


LOOOOOOOLLLL omg. THANK YOU. I have truly kicked myself.:smile:
 
Also, how would ou go about solving this inequality:S?:

|x+2| <3|x|

I don't know if you can apply the rule I used before again to this question.

Thanks.
 
Break it into 3 parts: x< -2, -2\le x &lt; 0, and 0\le x.
 

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