Question on lim x→1 (x − 5) / (x^2 + 2x − 4) ?

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SUMMARY

The limit expression lim x→1 (x − 5) / (x^2 + 2x − 4) cannot be simplified by factoring the quadratic in the denominator. The right-hand side evaluates to 4, but the left-hand side requires the application of L'Hôpital's Rule to determine its limit as x approaches 1. By applying L'Hôpital's Rule, the limit can be evaluated directly without factoring, confirming that the statement is false.

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Homework Statement



Determine whether the statement is true or false. lim x→1 (x − 5) / (x^2 + 2x − 4) = lim x→1 (x − 5) / lim x→1 (x^2 + 2x − 4)?

Homework Equations


[/B]

The Attempt at a Solution


I know that the right side of this equation and the left side have to equal each other in order for this to be true. On the right hand side the answer is 4. I don't know how to solve the left hand side because (x^2 + 2x − 4) cannot be factored.
 
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alaa amed said:

Homework Statement



Determine whether the statement is true or false. lim x→1 (x − 5) / (x^2 + 2x − 4) = lim x→1 (x − 5) / lim x→1 (x^2 + 2x − 4)?

Homework Equations


[/B]

The Attempt at a Solution


I know that the right side of this equation and the left side have to equal each other in order for this to be true. On the right hand side the answer is 4. I don't know how to solve the left hand side because (x^2 + 2x − 4) cannot be factored.
That's irrelevant. Can the limit of the LHS expression be evaluated without factoring the quadratic?
 

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