- #1
Rasine
- 208
- 0
(2x+3)/(x+1)^2
so this is what i am thinking...but it does not make sense
=(A/x+1)+(B/(x+1)^2)
so then 2x+3=A(x+1)^2+B(x+1)
2x+3=Ax^2+A2x+A+Bx+1
so that would make...
0=A
2=2A+B
3=A+B
this solution does not make any sense becuase if A=0 then according to the second equation B=2 which is not what B would equal in the third equation.
what am i doing wrong?
so this is what i am thinking...but it does not make sense
=(A/x+1)+(B/(x+1)^2)
so then 2x+3=A(x+1)^2+B(x+1)
2x+3=Ax^2+A2x+A+Bx+1
so that would make...
0=A
2=2A+B
3=A+B
this solution does not make any sense becuase if A=0 then according to the second equation B=2 which is not what B would equal in the third equation.
what am i doing wrong?