How to Solve Problems in Arithmetic Series Using Formulas?

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SUMMARY

This discussion focuses on solving problems in arithmetic series using specific formulas. The key formulas mentioned are the arithmetic mean, An = A1 + (n-1)d, and the arithmetic series sum, Sn = n/2 (A1 + An). The participants clarified how to apply these formulas to find the first term A1 when given S10 = -20 and d = 4, and to calculate S12 for the series starting with 2, 5, 8, etc. The simplification of Sn to Sn = n/2 [2A1 + (n-1)d] was also highlighted as a crucial step in solving these problems.

PREREQUISITES
  • Understanding of arithmetic series and sequences
  • Familiarity with the formulas for arithmetic means and series
  • Basic algebra skills for manipulating equations
  • Knowledge of how to substitute values into formulas
NEXT STEPS
  • Practice solving arithmetic series problems using Sn = n/2 (A1 + An)
  • Explore variations of arithmetic series with different initial terms and common differences
  • Learn about geometric series and how they differ from arithmetic series
  • Investigate real-world applications of arithmetic series in finance and statistics
USEFUL FOR

Students, educators, and anyone interested in mastering arithmetic series and enhancing their problem-solving skills in mathematics.

bananaman13
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I don't understand on how to get the answer of a certain problem in arithmetic series.

formula/s:

Arithmetic means

An=A1+ (n-1)d

Arithmetic series

Sn=n/2 (A1+An)

I understand on how to get the terms to these but when finding for:

Find A1 if,
S10= -20 , d= 4

&

Find S12 if, 2+5+8+...

I couldn't quite grasp the idea on how to apply the formulas to these problems.

Any help is appreciated. Thank you very much
 
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Sn=n/2 (A1+An)

this can also be written as Sn=n/2 (A1+(A1+ (n-1)d))

which then further simplifies to: Sn=n/2 (2A1+ (n-1)d)

now plug in the known values and simplify

for your first question, the value of n=10

for your second question,
n=12,d=3,A1=2
 
Thank you so much.

So, in which case,

Sn=n/2 (A1+An) is still equal to
Sn=n/2 [2A1+(n-1)d]

Just different in how to solve it.
 

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